MySQL - clausola IN
Puoi usare IN clausola per sostituire molti OR condizioni
Capire IN clausola, considera un employee_tbl tabella, che contiene i seguenti record:
mysql> SELECT * FROM employee_tbl;
+------+------+------------+--------------------+
| id | name | work_date | daily_typing_pages |
+------+------+------------+--------------------+
| 1 | John | 2007-01-24 | 250 |
| 2 | Ram | 2007-05-27 | 220 |
| 3 | Jack | 2007-05-06 | 170 |
| 3 | Jack | 2007-04-06 | 100 |
| 4 | Jill | 2007-04-06 | 220 |
| 5 | Zara | 2007-06-06 | 300 |
| 5 | Zara | 2007-02-06 | 350 |
+------+------+------------+--------------------+
7 rows in set (0.00 sec)
Ora, supponiamo in base alla tabella sopra di voler visualizzare record con daily_typing_pages uguali a 250 e 220 e 170. Questo può essere fatto usando OR condizioni come segue
mysql>SELECT * FROM employee_tbl
->WHERE daily_typing_pages= 250 OR
->daily_typing_pages= 220 OR daily_typing_pages= 170;
+------+------+------------+--------------------+
| id | name | work_date | daily_typing_pages |
+------+------+------------+--------------------+
| 1 | John | 2007-01-24 | 250 |
| 2 | Ram | 2007-05-27 | 220 |
| 3 | Jack | 2007-05-06 | 170 |
| 4 | Jill | 2007-04-06 | 220 |
+------+------+------------+--------------------+
4 rows in set (0.02 sec)
Lo stesso può essere ottenuto utilizzando IN clausola come segue -
mysql> SELECT * FROM employee_tbl
-> WHERE daily_typing_pages IN ( 250, 220, 170 );
+------+------+------------+--------------------+
| id | name | work_date | daily_typing_pages |
+------+------+------------+--------------------+
| 1 | John | 2007-01-24 | 250 |
| 2 | Ram | 2007-05-27 | 220 |
| 3 | Jack | 2007-05-06 | 170 |
| 4 | Jill | 2007-04-06 | 220 |
+------+------+------------+--------------------+
4 rows in set (0.02 sec)
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